Answer
(a) $f(g(x)) = \sqrt{x-3}$
(b) $Domain_{f(g(x))}: x \geq 3$
Work Step by Step
$$f(x) = \sqrt{x}$$ $$g(x) = x-3$$
$f(g(x)) = \sqrt{x-3}$
$Domain_{f(g(x))}: x-3 \geq 0$
$Domain_{f(g(x))}: x \geq 3$
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