College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.6 - Page 298: 52

Answer

$(f$ o $g)(x) = 3x -15$ $(g$ o $f)(x) = 3x -5$ $(f$ o $g)(2) = -9$ $(g$ o $f)(2) = 1$

Work Step by Step

$f(x) = 3x$ $g(x) = x- 5$ a) $(f$ o $g)(x)$ $(f$ o $g)(x) = f(g(x))$ $f(x-5) = 3(x-5)$ $= 3x - 15$ b) $(g$ o $f)(x)$ $(g$ o $f)(x) = g(f(x))$ $g(f(x)) = (3x) - 5$ $= 3x - 5$ c) $(f$ o $g)(2)$ $(f$ o $g)(2) = f(g(2))$ $f(2-5) = 3(2-5)$ $= 3(-3)$ $= -9$ d) $(g$ o $f)(2)$ $(g$ o $f)(2) = g(f(2))$ $g(f(2)) = (3(2)) - 5$ $= 6 - 5$ $= 1$
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