Answer
$f+g,f-g,fg,f/g$ : for all $x$ different from $-3$ and $2$
Work Step by Step
$f(x)+g(x)=8x/(x-2) + 6/(x+3)=(8x^2+30x-12)/(x^2+x-6)$
for all $x\ne{-3, 2}$
$f(x)-g(x)=8x/(x-2) - 6/(x+3)=(8x^2+18x-12)/(x^2+x-6)$
for all $x\ne{-3, 2}$
$f(x)\times g(x)=8x/(x-2) \times 6/(x+3)=48x/(x^2+x-6)$
for all $x\ne{-3, 2}$
$f(x)/g(x)=8x/(x-2) \div 6/(x+3)=(8x^2+24x)/(6x-12)$
for all $x\ne{-3, 2}$
