College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.6 - Page 298: 57

Answer

a) $(f$ o $g)(x) = x^{4} - 4x^{2}+6$ b) $(g$ o $f)(x) = x^{4} + 4x^{2} + 2$ c) $(f$ o $g)(2) = 6$ d) $(g$ o $f)(2) = 34$

Work Step by Step

$f(x) = x^{2} + 2$ $g(x) = x^{2} - 2$ a) $(f$ o $g)(x)$ $= f(g(x))$ $= f(x^{2} - 2)$ $= (x^{2} - 2)^{2} + 2$ $= [x^{2}(x^{2} - 2) -2(x^{2} - 2)] + 2$ $= x^{4}-4x^{2} + 4 + 2$ $= x^{4} - 4x^{2}+6$ b) $(g$ o $f)(x)$ $= g(f(x))$ $= g(x^{2} + 2)$ $= (x^{2} + 2)^{2} - 2$ $= [x^{2}(x^{2} + 2) +2(x^{2} + 2)] - 2$ $= x^{4} + 4x^{2} + 4 - 2$ $= x^{4} + 4x^{2} + 2$ c) $(f$ o $g)(2)$ $= f(g(2))$ $= f((2)^{2} - 2)$ $= f(4-2)$ $= f(2)$ $= (2)^{2} + 2$ $= 4 + 2$ $= 6$ d) $(g$ o $f)(2)$ $= g(f(2))$ $= g((2)^{2} + 2)$ $= g(4 + 2)$ $= g(6)$ $= (6)^{2} - 2$ $= 36 - 2$ $= 34$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.