Answer
(a) $f(g(x)) = \sqrt{x - 2}$
(b) $Domain_{f(g(x))}: x\geq 2$
Work Step by Step
$$f(x) = \sqrt{x}$$ $$g(x) = x -2$$
$f(g(x)) = \sqrt{x - 2}$
$Domain_{f(g(x))}: x-2 \geq 0$
$Domain_{f(g(x))}: x\geq 2$
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