College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 636: 78

Answer

$\sum_{i=1}^{15}(\frac{5}{1+i})$ or $5\cdot\sum_{i=1}^{15}(\frac{1}{1+i})$

Work Step by Step

We can see that the number in the denominator, the second part of the addition is changing from 1 to 15 with steps of 1. Therefore this will be our variable, and the first part of the addition in the denominator and the nominator are not changing. We can write that the sum is: $\sum_{i=1}^{15}(\frac{5}{1+i})=5\cdot\sum_{i=1}^{15}\frac{1}{1+i}$
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