College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 636: 76

Answer

$973$

Work Step by Step

$$\sum_{i=1}^6 (i^2+2i^3)=$$ $$=\sum_{i=1}^6 i^2 +\sum_{i=1}^6 2i^3=$$ $$=\sum_{i=1}^6 i^2 +2\sum_{i=1}^6 i^3=$$ $$=\frac{6(6+1)(2\cdot 6+1)}{6}+2\cdot \frac{6^2(6+1)^2}{4}=$$ $$=91+882=973$$
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