College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 636: 57

Answer

$\dfrac{23}{12}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given summation expression, $ \displaystyle\sum_{i=2}^5 \dfrac{x_i+1}{x_i+2} ,$ substitute $ i $ with the values from $ 2 $ to $ 5 .$ Then substitute the given values for each $x_i$'s $\bf{\text{Solution Details:}}$ Substituting $ i $ with the numbers from $ 2 $ to $ 5 ,$ the given expression is equivalent to \begin{array}{l}\require{cancel} \dfrac{x_2+1}{x_2+2}+\dfrac{x_3+1}{x_3+2}+\dfrac{x_4+1}{x_4+2}+\dfrac{x_5+1}{x_5+2} .\end{array} Using the given values $x_2=-1, x_3=0, x_4=1,$ and $x_5=2,$ the expression above evaluates to \begin{array}{l}\require{cancel} \dfrac{-1+1}{-1+2}+\dfrac{0+1}{0+2}+\dfrac{1+1}{1+2}+\dfrac{2+1}{2+2} \\\\= \dfrac{0}{1}+\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4} \\\\= 0+\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4} \\\\= \dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4} \\\\= \dfrac{6}{12}+\dfrac{8}{12}+\dfrac{9}{12} \\\\= \dfrac{23}{12} .\end{array}
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