Answer
$220$
Work Step by Step
$$\sum_{i=1}^5 (4i^2-2i+6)=$$
$$=\sum_{i=1}^5 4i^2 -\sum_{i=1}^5 2i+ \sum_{i=1}^5 6=$$
$$=4\sum_{i=1}^5 i^2 -2\sum_{i=1}^5 i+ \sum_{i=1}^5 6=$$
$$=4\cdot\frac{5(5+1)(2\cdot 5+1)}{6}-2\cdot \frac{5(5+1)}{2}+6\cdot 5=$$
$$=220-30+30=220$$
