College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 636: 69

Answer

$1,240$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given expression, $ \displaystyle\sum_{i=1}^{15} i^2 ,$ use the properties of summation. $\bf{\text{Solution Details:}}$ Using a property of the summation which is given by $\displaystyle\sum_{i=1}^n i^2=\dfrac{n(n+1)(2n+1)}{6},$ the expression above is equivalent to \begin{array}{l}\require{cancel} \dfrac{15(15+1)(2(15)+1)}{6} \\\\= \dfrac{15(16)(30+1)}{6} \\\\= \dfrac{\cancel3\cdot5(\cancel2\cdot8)(31)}{\cancel2\cancel3} \\\\= 5(8)(31) \\\\= 1,240 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.