College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 636: 77


$\sum_{i=1}^9(\frac{1}{3i})$ or $\frac{1}{3}\sum_{i=1}^{9}(\frac{1}{i})$

Work Step by Step

We can see that the number in the denominator, in brackets is changing from 1 to 9, with steps of 1. Therefore this will be our variable, and the $\frac{1}{3}$ is constant in all the fractions in the series. We can write that the sum is: $\sum_{i=1}^9(\frac{1}{3i})=\frac{1}{3}\sum_{i=1}^{9}\frac{1}{i}$
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