College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 636: 70

Answer

$3,251,250$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given expression, $ \displaystyle\sum_{i=1}^{50} 2i^3 ,$ use the properties of summation. $\bf{\text{Solution Details:}}$ Using a property of the summation which is given by $\displaystyle\sum_{i=1}^n ca_i=c\displaystyle\sum_{i=1}^n a_i,$ with $c= 2 ,$ the expression above is equivalent to \begin{array}{l}\require{cancel} 2\displaystyle\sum_{i=1}^{50} i^3 .\end{array} Using a property of the summation which is given by $\displaystyle\sum_{i=1}^n i^3=\dfrac{n^2(n+1)^2}{4},$ with $n= 50 ,$ the expression above is equivalent to \begin{array}{l}\require{cancel} 2\left( \dfrac{50^2(50+1)^2}{4} \right) \\\\= 2\left( \dfrac{50^2(51)^2}{4} \right) \\\\= 3,251,250 .\end{array}
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