Answer
$304$
Work Step by Step
$$\sum_{i=1}^4 (3i^3+2i-4)=$$
$$=\sum_{i=1}^4 3i^3 +\sum_{i=1}^4 2i- \sum_{i=1}^4 4=$$
$$=3\sum_{i=1}^4 i^3 +2\sum_{i=1}^4 i- \sum_{i=1}^4 4=$$
$$=3\cdot\frac{4^2(4+1)^2}{4}+2\cdot \frac{4(4+1)}{2}-4\cdot 4=$$
$$=300+20-16=304$$
