College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 459: 66


$9\log _{3}x$

Work Step by Step

We use the rules of logarithms to obtain: $21\log _{3}\sqrt [3] {x}+\log _{3}9x^{2}-\log _{3}9=\log _{3}\dfrac {\left( \sqrt [3] {x}\right) ^{21}\times 9x^{2}}{9}=\log _{3}x^{9}=9\log _{3}x$
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