## College Algebra (10th Edition)

RECALL: (1) $\log_a{P} -\log_a{Q} = \log_a{\left(\dfrac{\log_a{P}}{\log_a{Q}}\right)}$ (2) $\log_a{P} + \log_a{Q} = \log{(PQ)}$ (3) $\log_a{P^n}=n\cdot \log_a{P}$ Use rules (1) and (3) above to obtain: $=\log_a{\left(\dfrac{x}{y}\right)}+\log_a{z^2}$ Use rule (2) above to obtain: $=\log_a{\left(\dfrac{x}{y} \cdot z^2\right)} \\=\log_a{\left(\dfrac{xz^2}{y}\right)}$ Thus, the answer is Option (b).