Answer
$1$
Work Step by Step
RECALL:
(1) $\log_a{P} + \log_a{Q}=\log_a{(PQ)}$
(2) $\log_a{a} = 1$
Use rule (1) above to obtain:
$\log_8{2} + \log_8{4} = \log_8{(2\cdot4)}=\log_8{8}$
Use rule (2) above to obtain:
$\log_8{8}=1$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 459: 19
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