## College Algebra (10th Edition)

RECALL: $e^{b\cdot \ln{a}}=a^b$ (a) $e^{2x} \ne 2^x$ (b) Using the property in the recall part above gives: $e^{x\cdot\ln{2}} = 2^x$ (c) $e^{\log_2{x}} \ne 2^x$ (d) Using the property in the recall part above gives: $e^{2\cdot\ln{x}} = x^2$ Thus, only the expression in Option (b) is equivalent to $2^x$.