College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 459: 34

Answer

$3b$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To write the given expression, $ \ln27 ,$ in terms of $a$ and $b,$ where $a=\ln2$ and $b=\ln3,$ use the laws of logarithms and substitution. $\bf{\text{Solution Details:}}$ The given expression is equivalent to \begin{array}{l}\require{cancel} \ln3^3 .\end{array} Using the Power Rule of Logarithms, which is given by $\log_b x^y=y\log_bx,$ the expression above is equivalent to: \begin{array}{l}\require{cancel} 3\ln3 .\end{array} By substitution, since $b=\ln3,$ the expression above is equivalent to: \begin{array}{l}\require{cancel} 3b .\end{array}
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