Answer
$\log_a{M} + \log_a{N}$
Work Step by Step
RECALL:
For any positive numbers $A$ and $B$, and real number $a\gt 0, a\ne1$,
$\log_a{AB}=\log_a{A} + \log_a{B}$
Thus,
$\log_a{MN}=\log_a{M} + \log_a{N}$
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