College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 459: 41

Answer

$1+\ln{x}$

Work Step by Step

RECALL: (1) $\ln{(MN)} = \ln{M} + \ln{N}$ (2) $\ln{\left(\dfrac{M}{N}\right)} = \ln{M} - \ln{N}$ (3) $\ln{e} = 1$ Using rule (1) above gives: $=\ln{e} + \ln{x}$ Using rule (3) above, the given expression simplifies to: $=1+\ln{x}$
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