Answer
$1+\ln{x}$
Work Step by Step
RECALL:
(1) $\ln{(MN)} = \ln{M} + \ln{N}$
(2) $\ln{\left(\dfrac{M}{N}\right)} = \ln{M} - \ln{N}$
(3) $\ln{e} = 1$
Using rule (1) above gives:
$=\ln{e} + \ln{x}$
Using rule (3) above, the given expression simplifies to:
$=1+\ln{x}$