Answer
$2+\log_5{x}$
Work Step by Step
RECALL:
(1) $\log_a{(MN)} = \log_a{M} + \log_a{N}$
(2) $\log_a{\left(\dfrac{M}{N}\right)} = \log_a{M} - \log_a{N}$
(3) $\log_a{a} = 1$
Note that $25=5(5)$. So the given expression is equivalent to:
$\log_5{(5\cdot5\cdot x)}$
Using rule (1) above, the given expression is equivalent to:
$=\log_5{5} + \log_5{5} + \log_5{x}$
Using rule (3) above, the expression above simplifies to:
$=1+1 + \log_5{x}
\\=2+\log_5{x}$
