Answer
$\log _{2}\left( \left( 3x-2\right) ^{4}x\right) $
Work Step by Step
We use the rules of logarithms to obtain:
$8\log _{2}\sqrt {3x-2}-\log _{2}\left( \dfrac {4}{x}\right) +\log _{2}4=\log _{2}\dfrac {\left( \sqrt {3x-2}\right) ^{8}\times 4}{\dfrac {4}{x}}=\log _{2}\left( \left( 3x-2\right) ^{4}x\right) $
