Answer
$\ln{x} -x$
Work Step by Step
RECALL:
(1) $\ln{(MN)} = \ln{M} + \ln{N}$
(2) $\ln{\left(\dfrac{M}{N}\right)} = \ln{M} - \ln{N}$
(3) $\ln{e} = 1$
(4) $\ln{(e^x)}=x$
Using rule (2) above, the given expression is equivalent to:
$=\ln{x} - \ln{(e^x)}$
Using rule (4) above, the given expression simplifies to:
$=\ln{x} -x$