College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding: 46

Answer

$\log _{2}a-2\log _{2}b$

Work Step by Step

We use the rules of logs to obtain: $\log _{2}\left( \dfrac {a}{b^{2}}\right) =\log _{2}a-\log _{2}b^{2}=\log _{2}a-2\log _{2}b$
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