Answer
$\log _{2}a-2\log _{2}b$
Work Step by Step
We use the rules of logs to obtain:
$\log _{2}\left( \dfrac {a}{b^{2}}\right) =\log _{2}a-\log _{2}b^{2}=\log _{2}a-2\log _{2}b$
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