Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 9



Work Step by Step

$1+cot^2x=csc^2x$ $cot^2x=csc^2x-1$ $tan~x=\frac{1}{cot~x}$ $tan~x~cot~x=1$ $tan^2x(csc^2x-1)=tan^2x~cot^2x=(tan~x~cot~x)^2=1^2=1$
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