Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 35


$x=0$ $x=\pi$ $x=\frac{\pi}{2}$

Work Step by Step

$cos^2x+sin^2x=1$ $cos^2x=1-sin^2x$ $cos^2x+sin~x=1$ $1-sin^2x+sin~x=1$ $-sin^2x+sin~x=0$ $-sin~x(sin~x-1)=0$ $-sin~x=0$ $sin~x=0$ $x=0$ or $x=\pi$ $sin~x-1=0$ $sin~x=1$ $x=\frac{\pi}{2}$
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