Answer
$x=0$
Work Step by Step
$cos^2x+sin^2x=1$
$sin^2x=1-cos^2x$
$sin^2x+2cos~x=2$
$1-cos^2x+2cos~x-2=0$
$cos^2x-2~cos~x+2-1=0$
$cos^2x-2~cos~x+1=0$
$(cos~x-1)^2=0$
$cos~x-1=0$
$cos~x=1$
$x=0$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 552: 36
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
