Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 12



Work Step by Step

$sec^2(-θ)=sec^2θ$ $sec~θ=\frac{1}{cos~θ}$ $csc~θ=\frac{1}{sin~θ}$ $\frac{sec^2(-θ)}{csc^2~θ}=\frac{\frac{1}{cos^2~θ}}{\frac{1}{sin^2~θ}}=\frac{1}{cos^2θ}\frac{sin^2θ}{1}=\frac{sin^2θ}{cos^2θ}=tan^2θ$
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