Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 11



Work Step by Step

$cot(\frac{\pi}{2}-u)=tan~u$ $\frac{1}{sec~u}=cos~u$ $\frac{cot(\frac{\pi}{2}-u)}{cos~u}=\frac{tan~u}{\frac{1}{sec~u}}=tan~u~sec~u$
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