Answer
$\frac{cot(\frac{\pi}{2}-u)}{cos~u}=tan~u~sec~u$
Work Step by Step
$cot(\frac{\pi}{2}-u)=tan~u$
$\frac{1}{sec~u}=cos~u$
$\frac{cot(\frac{\pi}{2}-u)}{cos~u}=\frac{tan~u}{\frac{1}{sec~u}}=tan~u~sec~u$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 552: 11
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