Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 13



Work Step by Step

$1+cot^2x=csc^2x=\frac{1}{sin^2x}$ $cos^2x+cos^2x~cot^2x=cos^2x(1+cot^2x)=cos^2x~csc^2x=cos^2x\frac{1}{sin^2x}=cot^2x$
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