Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 8



Work Step by Step

$sin^2θ+cos^2θ=1$ $sin^2θ=1-cos^2θ$ $tan~θ=\frac{sin~θ}{cos~θ}$ $\frac{tan~θ}{1-cos^2θ}=\frac{\frac{sin~θ}{cos~θ}}{sin^2θ}=\frac{1}{sin~θ~cos~θ}=csc~θ~sec~θ$
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