Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 21


The identity is verified. $sin(\frac{\pi}{2}-θ)~tan~θ=sin~θ$

Work Step by Step

$sin(\frac{\pi}{2}-θ)=cos~θ$ $tan~θ=\frac{sin~θ}{cos~θ}$ $sin(\frac{\pi}{2}-θ)~tan~θ=cos~θ~\frac{sin~θ}{cos~θ}=sin~θ$
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