Answer
The identity is verified.
$sin(\frac{\pi}{2}-θ)~tan~θ=sin~θ$
Work Step by Step
$sin(\frac{\pi}{2}-θ)=cos~θ$
$tan~θ=\frac{sin~θ}{cos~θ}$
$sin(\frac{\pi}{2}-θ)~tan~θ=cos~θ~\frac{sin~θ}{cos~θ}=sin~θ$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 552: 21
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