Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 552: 19


The identity is verified. $cos~x~(1+tan^2x)=sec~x$

Work Step by Step

$1+tan^2x=sec^2x~~$ (Pythagorean identity): $cos~x=\frac{1}{sec~x}$ $cos~x~(1+tan^2x)=cos~x~sec^2x=\frac{1}{sec~x}~sec^2x=sec~x$
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