Answer
$cot^2x(sin^2x)=cos^2x$
Work Step by Step
$cot~x=\frac{cos~x}{sin~x}$
$cot^2x(sin^2x)=(\frac{cos~x}{sin~x})^2(sin^2x)=\frac{cos^2~x}{sin^2~x}(sin^2x)=cos^2x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 552: 10
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