Answer
$\dfrac{\sqrt{15}+1}{2}=\dfrac{7}{\sqrt{15}-1}$
Work Step by Step
$\dfrac{\sqrt{15}+1}{2}$
Multiply the numerator and the denominator of this expression by the conjugate of the numerator and simplify if possible:
$\dfrac{\sqrt{15}+1}{2}=\dfrac{\sqrt{15}+1}{2}\cdot\dfrac{\sqrt{15}-1}{\sqrt{15}-1}=\dfrac{(\sqrt{15})^{2}-1^{2}}{2(\sqrt{15}-1)}=...$ $...=\dfrac{15-1}{2(\sqrt{15}-1)}=\dfrac{14}{2(\sqrt{15}-1)}=\dfrac{7}{\sqrt{15}-1}$
