Answer
$\dfrac{\sqrt[3]{4x}}{\sqrt[3]{z^{4}}}=\dfrac{2x}{z\sqrt[3]{2x^{2}z}}$
Work Step by Step
$\dfrac{\sqrt[3]{4x}}{\sqrt[3]{z^{4}}}$
First, simplify this expression:
$\dfrac{\sqrt[3]{4x}}{\sqrt[3]{z^{4}}}=\dfrac{\sqrt[3]{4x}}{z\sqrt[3]{z}}=...$
Multiply this fraction by $\dfrac{\sqrt[3]{2x^{2}}}{\sqrt[3]{2x^{2}}}$ and simplify again if possible:
$...=\dfrac{\sqrt[3]{4x}}{z\sqrt[3]{z}}\cdot\dfrac{\sqrt[3]{2x^{2}}}{\sqrt[3]{2x^{2}}}=\dfrac{\sqrt[3]{8x^{3}}}{z\sqrt[3]{2x^{2}z}}=\dfrac{2x}{z\sqrt[3]{2x^{2}z}}$
