## Algebra: A Combined Approach (4th Edition)

$\dfrac{\sqrt{4x}}{7}=\dfrac{4x}{7\sqrt{4x}}$
$\dfrac{\sqrt{4x}}{7}$ Multiply this expression by $\dfrac{\sqrt{4x}}{\sqrt{4x}}$ and simplify if possible: $\dfrac{\sqrt{4x}}{7}=\dfrac{\sqrt{4x}}{7}\cdot\dfrac{\sqrt{4x}}{\sqrt{4x}}=\dfrac{\sqrt{(4x)^{2}}}{7\sqrt{4x}}=\dfrac{4x}{7\sqrt{4x}}$