Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set: 49

Answer

$\dfrac{\sqrt{4x}}{7}=\dfrac{4x}{7\sqrt{4x}}$

Work Step by Step

$\dfrac{\sqrt{4x}}{7}$ Multiply this expression by $\dfrac{\sqrt{4x}}{\sqrt{4x}}$ and simplify if possible: $\dfrac{\sqrt{4x}}{7}=\dfrac{\sqrt{4x}}{7}\cdot\dfrac{\sqrt{4x}}{\sqrt{4x}}=\dfrac{\sqrt{(4x)^{2}}}{7\sqrt{4x}}=\dfrac{4x}{7\sqrt{4x}}$
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