Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 718: 53

Answer

$\sqrt{\dfrac{2}{5}}=\dfrac{2}{\sqrt{10}}$

Work Step by Step

$\sqrt{\dfrac{2}{5}}$ Rewrite this expression as $\dfrac{\sqrt{2}}{\sqrt{5}}$: $\sqrt{\dfrac{2}{5}}=\dfrac{\sqrt{2}}{\sqrt{5}}=...$ Multiply this fraction by $\dfrac{\sqrt{2}}{\sqrt{2}}$ and simplify: $...=\dfrac{\sqrt{2}}{\sqrt{5}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{\sqrt{2^{2}}}{\sqrt{10}}=\dfrac{2}{\sqrt{10}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.