Answer
$\dfrac{\sqrt[3]{5y^{2}}}{\sqrt[3]{4x}}=\dfrac{5y}{\sqrt[3]{100xy}}$
Work Step by Step
$\dfrac{\sqrt[3]{5y^{2}}}{\sqrt[3]{4x}}$
Multiply this expression by $\dfrac{\sqrt[3]{25y}}{\sqrt[3]{25y}}$ and simplify if possible:
$\dfrac{\sqrt[3]{5y^{2}}}{\sqrt[3]{4x}}=\dfrac{\sqrt[3]{5y^{2}}}{\sqrt[3]{4x}}\cdot\dfrac{\sqrt[3]{25y}}{\sqrt[3]{25y}}=\dfrac{\sqrt[3]{125y^{3}}}{\sqrt[3]{100xy}}=\dfrac{5y}{\sqrt[3]{100xy}}$