Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 718: 56

Answer

$\dfrac{\sqrt{y}}{7}=\dfrac{y}{7\sqrt{y}}$

Work Step by Step

$\dfrac{\sqrt{y}}{7}$ Multiply this expression by $\dfrac{\sqrt{y}}{\sqrt{y}}$ and simplify if possible: $\dfrac{\sqrt{y}}{7}=\dfrac{\sqrt{y}}{7}\cdot\dfrac{\sqrt{y}}{\sqrt{y}}=\dfrac{\sqrt{y^{2}}}{7\sqrt{y}}=\dfrac{y}{7\sqrt{y}}$
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