Answer
$\dfrac{2-\sqrt{11}}{6}=-\dfrac{7}{6(2+\sqrt{11})}$
Work Step by Step
$\dfrac{2-\sqrt{11}}{6}$
Multiply the numerator and the denominator of this expression by the conjugate of the numerator and simplify if possible:
$\dfrac{2-\sqrt{11}}{6}=\dfrac{2-\sqrt{11}}{6}\cdot\dfrac{2+\sqrt{11}}{2+\sqrt{11}}=\dfrac{2^{2}-(\sqrt{11})^{2}}{6(2+\sqrt{11})}=...$ $...=\dfrac{4-11}{6(2+\sqrt{11})}=\dfrac{-7}{6(2+\sqrt{11})}=-\dfrac{7}{6(2+\sqrt{11})}$
