Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 48

Answer

$5x^2\sqrt{5}$

Work Step by Step

Using $\sqrt[n]{\dfrac{x}{y}}=\dfrac{\sqrt[n]{x}}{\sqrt[n]{y}},$ the given expression, $ \dfrac{15\sqrt{60x^5}}{3\sqrt{12x}} ,$ is equivalent to \begin{align*} & \dfrac{15}{3}\sqrt{\dfrac{60x^5}{12x}} \\\\&= 5\sqrt{5x^4} .\end{align*} Extracting the perfect powers of the index, the expression above is equivalent to \begin{align*} & 5\sqrt{x^4\cdot5} \\&= 5\sqrt{(x^2)^2\cdot5} \\&= 5(x^2)\sqrt{5} \\&= 5x^2\sqrt{5} .\end{align*} Hence, the simplified form of the given expression is $ 5x^2\sqrt{5} $.
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