Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 35

Answer

$4xy^2\sqrt[3]{y}$

Work Step by Step

Extracting the perfect powers of the index, the given expression, $ 2\sqrt[3]{2xy^2}\cdot\sqrt[3]{4x^2y^5} ,$ is equivalent to \begin{align*} & =2\sqrt[3]{2xy^2}\cdot\sqrt[3]{y^3\cdot4x^2y^2} \\\\&= 2\sqrt[3]{2xy^2}\cdot\sqrt[3]{(y)^3\cdot4x^2y^2} \\\\&= 2\sqrt[3]{2xy^2}\cdot y\sqrt[3]{4x^2y^2} .\end{align*} Using $a\sqrt[n]{x}\cdot b\sqrt[n]{y}=ab\sqrt[n]{xy},$ the expression above is equivalent to \begin{align*} & =2(y)\sqrt[3]{2xy^2(4x^2y^2)} \\\\&= 2y\sqrt[3]{8x^3y^4} .\end{align*} Extracting the perfect powers of the index, the expression above is equivalent to \begin{align*} & =2y\sqrt[3]{8x^3y^3\cdot y} \\\\&= 2y\sqrt[3]{(2xy)^3\cdot y} \\\\&= 2y(2xy)\sqrt[3]{y} \\\\&= 4xy^2\sqrt[3]{y} .\end{align*} Hence, the simplified form of the given expression is $ 4xy^2\sqrt[3]{y} $.
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