Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 27

Answer

$-2xy\sqrt[5]{xy^2} $

Work Step by Step

Extracting the perfect powers of the index, the given expression, $ \sqrt[5]{-32x^6y^7} ,$ is equivalent to \begin{align*} & =\sqrt[5]{-32x^5y^5\cdot xy^2} \\\\&= \sqrt[5]{(-2xy)^5\cdot xy^2} \\\\&= -2xy\sqrt[5]{xy^2} .\end{align*} Hence, the simplified form of the given expression is $ -2xy\sqrt[5]{xy^2} $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.