Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 45

$\dfrac{\sqrt[3]{4x}}{2}$

We multiply $\sqrt[3]{2^2}$ to both the numerator and the denominator to remove the radical from the denominator: $=\dfrac{\sqrt[3]{x} \cdot \sqrt[3]{2^2}}{\sqrt[3]{2} \cdot \sqrt[3]{2^2}}$ $=\dfrac{\sqrt[3]{x\cdot 2^2}}{\sqrt[3]{2^3}}$ $=\dfrac{\sqrt[3]{4x}}{2}$