Answer
$-6$
Work Step by Step
RECALL:
$\sqrt[3]{a} \cdot \sqrt[3]{b} = \sqrt[3]{a\cdot b}$.
Use the rule above to have
$\sqrt[3]{9(-24)}
\\=\sqrt[3]{-216}
\\=\sqrt[3]{(-6)^3}
\\=-6.$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 16
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