Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 47

Answer

$\dfrac{\sqrt[4]{250}}{5}$

Work Step by Step

Multiplying the numerator and the denominator by an expression equal to $1$ which will make the denominator a perfect power of the index, the given expression, $ \dfrac{\sqrt[4]{2}}{\sqrt[4]{5}} ,$ is equivalent to \begin{align*} & =\dfrac{\sqrt[4]{2}}{\sqrt[4]{5}}\cdot\dfrac{\sqrt[4]{5^3}}{\sqrt[4]{5^3}} \\\\&= \dfrac{\sqrt[4]{2(5^3)}}{\sqrt[4]{5^4}} \\\\&= \dfrac{\sqrt[4]{250}}{5} .\end{align*} Hence, the simplified form of the given expression is $ \dfrac{\sqrt[4]{250}}{5} $.
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