Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 38



Work Step by Step

The variables are assumed to be non-zero since they are also in the denominator. RECALL: $\dfrac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$ where $a$ and $b$ are non-negative and $b\ne0.$ Use the rule above to have $\sqrt{\dfrac{48x^3}{3xy^2}} \\=\sqrt{\dfrac{16x^2}{y^2}} \\=\sqrt{\left(\dfrac{4x}{y}\right)^2} \\=\dfrac{4x}{y}.$
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