Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises: 29

Answer

$8|y^3|\sqrt{5y}$

Work Step by Step

RECALL: $\sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b}, a\gt0, b\gt 0.$ Use the rule above to have $\sqrt{(8y^5)(40y^2)} \\=\sqrt{64y^6(5y)} \\=\sqrt{(8y^3)^2(5y)} \\=8|y^3|\sqrt{5y}.$
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