Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 36

Answer

$3a^2\sqrt[4]{108a^2b^2}$

Work Step by Step

Extracting the perfect powers of the index, the given expression, $ 3\sqrt[4]{18a^9}\cdot\sqrt[4]{6ab^2} ,$ is equivalent to \begin{align*} & 3\sqrt[4]{a^8\cdot18a}\cdot\sqrt[4]{6ab^2} \\\\&= 3\sqrt[4]{(a^2)^4\cdot18a}\cdot\sqrt[4]{6ab^2} \\\\&= 3a^2\sqrt[4]{18a}\cdot\sqrt[4]{6ab^2} .\end{align*} Using $a\sqrt[n]{x}\cdot b\sqrt[n]{y}=ab\sqrt[n]{xy},$ the expression above is equivalent to \begin{align*} & 3a^2\sqrt[4]{18a(6ab^2)} \\\\&= 3a^2\sqrt[4]{108a^2b^2} .\end{align*} Hence, the simplified form of the given expression is $ 3a^2\sqrt[4]{108a^2b^2} $.
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